- Code: Select all
*-----------*
|...|...|41.|
|4..|...|..7|
|..9|.8.|.3.|
|---+---+---|
|..3|5..|.76|
|8..|1.6|..3|
|76.|..8|5..|
|---+---+---|
|.7.|.6.|1..|
|5..|...|..2|
|.38|...|...|
*-----------*
Play/Print this puzzle online
April 13, 2014
18 posts
• Page 1 of 2 • 1, 2
April 13, 2014
by ArkieTech » Sun Apr 13, 2014 12:05 am
Play/Print this puzzle online
dan
-
ArkieTech - Posts: 3355
- Joined: 29 May 2006
- Location: NW Arkansas USA
Re: April 13, 2014
by Leren » Sun Apr 13, 2014 1:17 am
- Code: Select all
*--------------------------------------------------------------*
| 3 58 7 | 6 25-9 25-9 | 4 1 a89 |
| 4 58 6 |c39 1359 1359 | 2-9 28-9 7 |
| 12 12 9 | 7 8 4 | 6 3 5 |
|--------------------+--------------------+--------------------|
| 129 1249 3 | 5 249 29 | 8 7 6 |
| 8 249 5 | 1 7 6 | 29 249 3 |
| 7 6 24 | 2349 2349 8 | 5 249 1 |
|--------------------+--------------------+--------------------|
|b29 7 b24 |b349 6 359 | 1 589 b489 |
| 5 49 1 | 8 49 7 | 3 6 2 |
| 6 3 8 | 249 12459 1259 | 7 59 49 |
*--------------------------------------------------------------*
ALS XY Wing: (9=8) r1c9 - (8=3) r7c1349 - (3=9) r2c4 => - 9 r1c56, r2c78; lclste
Leren
- Leren
- Posts: 5117
- Joined: 03 June 2012
Re: April 13, 2014
by SteveG48 » Sun Apr 13, 2014 2:34 am
- Code: Select all
*---------------------------------------------------------------------*
| 3 58 7 | 6 259 259 | 4 1 89 |
| 4 58 6 | a3-9 1359 1359 |b29 289 7 |
| 12 12 9 | 7 8 4 | 6 3 5 |
*----------------------+-----------------------+----------------------|
| 129 1249 3 | 5 249 29 | 8 7 6 |
| 8 249 5 | 1 7 6 |c29 249 3 |
| 7 6 d24 |bd2349 eg2349 8 | 5 d249 1 |
*----------------------+-----------------------+----------------------|
| 29 7 24 |be349 6 359 | 1 589 489 |
| 5 49 1 | 8 f49 7 | 3 6 2 |
| 6 3 8 | 249 12459 1259 | 7 59 49 |
*---------------------------------------------------------------------*
I'll toss this one out for discussion since I can't find a better single-stepper.
The idea is that a 9 in r2c4 would eliminate all candidates in r6c5:
(9)r2c4 - *r67c4|r2c7 = r5c7 - (9=**234)r6c348 - (3*9=4)r7c4 - (4=9)r8c5 - (9**234)r6c5 => -9 r2c4 ; stte
Last edited by SteveG48 on Sun Apr 13, 2014 1:41 pm, edited 1 time in total.
Steve
-
SteveG48 - 2019 Supporter
- Posts: 4479
- Joined: 08 November 2013
- Location: Orlando, Florida
Re: April 13, 2014
by daj95376 » Sun Apr 13, 2014 4:53 am
SteveG48 wrote:
- Code: Select all
*---------------------------------------------------------------------*
| 3 58 7 | 6 259 259 | 4 1 89 |
| 4 58 6 | a3-9 1359 1359 |b29 289 7 |
| 12 12 9 | 7 8 4 | 6 3 5 |
*----------------------+-----------------------+----------------------|
| 129 1249 3 | 5 249 29 | 8 7 6 |
| 8 249 5 | 1 7 6 |c29 249 3 |
| 7 6 d24 |bd2349 eg2349 8 | 5 d249 1 |
*----------------------+-----------------------+----------------------|
| 29 7 24 |be349 6 359 | 1 589 489 |
| 5 49 1 | 8 f49 7 | 3 6 2 |
| 6 3 8 | 249 12459 1259 | 7 59 49 |
*---------------------------------------------------------------------*
I'll toss this one out for discussion since I can't find a better single-stepper.
The idea is that a 9 in r2c4 would eliminate all candidates in r6c5:
(9)r2c4 - *r67c4|r2c7 = r5c7 - (9=**234)r6c348 - (3*9=4)r7c4 - (4=9)r8c5 - (9**234)r6c5 => -9 r2c4 ; stte
You could have ended your sequence early:
(9)r2c4 - *r67c4|r2c7 = r5c7 - (9=**234)r6c348 - (3*9=4)r7c4 - (4=9)r8c5; contradiction [r6]<>9 => -9r2c4
Last edited by daj95376 on Sun Apr 13, 2014 5:26 pm, edited 1 time in total.
- daj95376
- 2014 Supporter
- Posts: 2624
- Joined: 15 May 2006
Re: April 13, 2014
by Leren » Sun Apr 13, 2014 6:00 am
Steve and Danny, there is a typo in your posts, I'm sure you mean .... - 9 r2c4
Leren
Leren
- Leren
- Posts: 5117
- Joined: 03 June 2012
Re: April 13, 2014
by pjb » Sun Apr 13, 2014 11:39 am
- Code: Select all
3 58 7 | 6 25-9 25-9 | 4 1 a89
4 58 6 |f39 1359 e1359 | 2-9 b28-9 7
12 12 9 | 7 8 4 | 6 3 5
---------------------+----------------------+---------------------
129 1249 3 | 5 249 29 | 8 7 6
8 249 5 | 1 7 6 | 29 249 3
7 6 24 | 2349 2349 8 | 5 249 1
---------------------+----------------------+---------------------
29 7 24 | 349 6 d359 | 1 c589 489
5 49 1 | 8 49 7 | 3 6 2
6 3 8 | 249 12459 1259 | 7 59 49
(9=8)r1c9 - r2c8 = (8-5)r7c8 = (5-3)r7c6 = r2c6 - (3=9)r2c4 => -9 r1c56, r2c78; stte
Phil
- pjb
- 2014 Supporter
- Posts: 2672
- Joined: 11 September 2011
- Location: Sydney, Australia
Re: April 13, 2014
by pjb » Sun Apr 13, 2014 12:23 pm
Leren, am I missing something? These eliminations solve it with singles in my hands..
Phil
Phil
- pjb
- 2014 Supporter
- Posts: 2672
- Joined: 11 September 2011
- Location: Sydney, Australia
Re: April 13, 2014
by ArkieTech » Sun Apr 13, 2014 12:29 pm
pjb wrote:Leren, am I missing something? These eliminations solve it with singles in my hands..
Phil
- Code: Select all
*-----------------------------------------------------------*
| 3 8 7 | 6 25 25 | 4 1 9 |
| 4 5 6 | 39 139 139 | 2 8 7 |
| 12 12 9 | 7 8 4 | 6 3 5 |
|-------------------+-------------------+-------------------|
| 129 1249 3 | 5 249 29 | 8 7 6 |
| 8 24 5 | 1 7 6 | 9 24 3 |
| 7 6 24 | 2349 2349 8 | 5 24 1 |
|-------------------+-------------------+-------------------|
| 29 7 24 | 349 6 359 | 1 59 8 |
| 5 49 1 | 8 49 7 | 3 6 2 |
| 6 3 8 | 29 1259 1259 | 7 59 4 |
*-----------------------------------------------------------*
24 pair in b4
dan
-
ArkieTech - Posts: 3355
- Joined: 29 May 2006
- Location: NW Arkansas USA
Re: April 13, 2014
by tlanglet » Sun Apr 13, 2014 1:32 pm
- Code: Select all
*--------------------------------------------------------------------*
| 3 58 7 | 6 259 259 | 4 1 89 |
| 4 58 6 | 39 1359 1359 | 29 289 7 |
|*12 *12 9 | 7 8 4 | 6 3 5 |
|----------------------+----------------------+----------------------|
|*129 *1249 3 | 5 249 29 | 8 7 6 |
| 8 24-9 5 | 1 7 6 | 29 249 3 |
| 7 6 24 | 2349 2349 8 | 5 249 1 |
|----------------------+----------------------+----------------------|
| 29 7 24 | 349 6 359 | 1 589 489 |
| 5 49 1 | 8 49 7 | 3 6 2 |
| 6 3 8 | 249 12459 1259 | 7 59 49 |
*--------------------------------------------------------------------*
AUR(12)r34c12[9r4c12=4r4c2]-(4=9)r8c2 => r5c2<>9
Ted
- tlanglet
- 2010 Supporter
- Posts: 538
- Joined: 29 May 2010
Re: April 13, 2014
by SteveG48 » Sun Apr 13, 2014 1:41 pm
Thanks Danny, Leren. Fixed typo. I'll leave the chain alone so people can see what Danny was commenting on.
Steve
-
SteveG48 - 2019 Supporter
- Posts: 4479
- Joined: 08 November 2013
- Location: Orlando, Florida
Re: April 13, 2014
by Luke » Sun Apr 13, 2014 5:51 pm
tlanglet wrote:
- Code: Select all
*--------------------------------------------------------------------*
| 3 58 7 | 6 259 259 | 4 1 89 |
| 4 58 6 | 39 1359 1359 | 29 289 7 |
|*12 *12 9 | 7 8 4 | 6 3 5 |
|----------------------+----------------------+----------------------|
|*129 *1249 3 | 5 249 29 | 8 7 6 |
| 8 24-9 5 | 1 7 6 | 29 249 3 |
| 7 6 24 | 2349 2349 8 | 5 249 1 |
|----------------------+----------------------+----------------------|
| 29 7 24 | 349 6 359 | 1 589 489 |
| 5 49 1 | 8 49 7 | 3 6 2 |
| 6 3 8 | 249 12459 1259 | 7 59 49 |
*--------------------------------------------------------------------*
AUR(12)r34c12[9r4c12=4r4c2]-(4=9)r8c2 => r5c2<>9
Yes, that's the ticket. I looked no further after reducing it to a Type 1 with this:
hp(12)r34c2=(2)r5c2-(2=4)r6c3 ==>r4c2<>4
-
Luke - 2015 Supporter
- Posts: 435
- Joined: 06 August 2006
- Location: Southern Northern California
Re: April 13, 2014
by daj95376 » Sun Apr 13, 2014 6:29 pm
_
While reviewing Steve's elimination, I noticed there was an almost 2-String Kite present. A two-step solution then emerged.
While reviewing Steve's elimination, I noticed there was an almost 2-String Kite present. A two-step solution then emerged.
- Code: Select all
+-----------------------------------------------------------------------+
| 3 58 7 | 6 259 259 | 4 1 89 |
| 4 58 6 | 39 1359 1359 | 29 289 7 |
| 12 12 9 | 7 8 4 | 6 3 5 |
|-----------------------+-----------------------+-----------------------|
| 129 1249 3 | 5 249 29 | 8 7 6 |
| 8 249 5 | 1 7 6 | 29 249 3 |
| 7 6 24 | 2349 2349 8 | 5 249 1 |
|-----------------------+-----------------------+-----------------------|
| 29 7 24 | 349 6 359 | 1 589 489 |
| 5 49 1 | 8 49 7 | 3 6 2 |
| 6 3 8 | 249 12459 1259 | 7 59 49 |
+-----------------------------------------------------------------------+
# 64 eliminations remain
ALS-XZ : (9=2)r4c6 - (2=49)r48c5 => -9 r6c5
Kite (9): r6c4 = r6c8 - r5c7 = r2c7 => -9 r2c4
- daj95376
- 2014 Supporter
- Posts: 2624
- Joined: 15 May 2006
Re: April 13, 2014
by blue » Sun Apr 13, 2014 6:55 pm
- Code: Select all
+---------------+----------------------+------------------+
| 3 58 7 | 6 259 259 | 4 1 89 |
| 4 58 6 | 3-9 1359 1359 | 2(9) 289 7 |
| 12 12 9 | 7 8 4 | 6 3 5 |
+---------------+----------------------+------------------+
| 129 1249 3 | 5 249 29 | 8 7 6 |
| 8 249 5 | 1 7 6 | 2(9) 249 3 |
| 7 6 24 | 24(39) 24(39) 8 | 5 24(9) 1 |
+---------------+----------------------+------------------+
| 29 7 24 | (349) 6 359 | 1 589 489 |
| 5 49 1 | 8 (49) 7 | 3 6 2 |
| 6 3 8 | 249 12459 1259 | 7 59 49 |
+---------------+----------------------+------------------+
This is another take on Steve's logic.
It must be related to Danny's post, above, but I haven't checked the details.
9r7c4 = [AIC: 3r6c5 = r6c4 - (3=4)r7c4 - (4=9)r8c5] - 9r6c5 = [Kite: 9r6c4 = r6c8 - r5c7 = 9r2c7] => r2c4<>9; stte
- blue
- Posts: 1045
- Joined: 11 March 2013
18 posts
• Page 1 of 2 • 1, 2
