Am I ever stuck

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Am I ever stuck

Postby Guest » Mon Apr 17, 2006 12:13 am

. 4 8 | 1 . . | . . 5
. 3 1 | . 5 . | . . .
5 7 2 |. 8 4| 1 . .
------+-------+------
4 8 6 |5 1 7| . . 3
2 9 5 |4 3 8|6 7 1
3 1 7 |9 6 2|4 5 8
------+-------+------
7 5 3 |2 4 1| . . 6
8 2 . | . 6 . |5 1 .
1 6 . | . 5 3| . . 1

Well ive gotten to this point and i was asking myself if it was possible to finish using ONLY logic. If it is, could anyone please give me the next step because im trying to take out all the possibilities one by one but im going in circles with my assumptions. Thanks a [Edited by Luna] load:)
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Sorry

Postby Guest » Mon Apr 17, 2006 12:14 am

Cant help ya, sorry.... probably cause im you and im replying to my own message....
Meh probably not
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Postby tarek » Mon Apr 17, 2006 12:26 am

Hi RobertoLuango,

You have 2 5s in column 5..............

tarek
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Re: Jesus Jesus am I ever stuck

Postby Imamess » Mon Apr 17, 2006 5:54 am

So do you want the answer, or a hint? This is my first post and I haven't looked at any others yet, why read posts when you can do a Suduko? Anyway, I don't know the naming methods you use. You should be able to figure out box 8. The middle one of the bottom 3. Of the missing 7,8 & 9 there is only one place where the 8 can go.
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Postby TKiel » Tue Apr 18, 2006 1:04 am

I'd like to see the answer.

Tracy
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Invalid Puzzle

Postby keith » Tue Apr 18, 2006 2:02 am

This one is pretty messed up.

There are two <5>'s in C5.
There is no place for a <3> in B9.
There is no place for a <3> in R8

Keith

.
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Postby Ruud » Tue Apr 18, 2006 2:36 am

I like to fix broken things.

Here is a repaired version:

Code: Select all
. 4 8|1 . .|. . 5
. 3 1|. . .|. . .
5 7 2|. 8 4|1 . .
-----+-----+-----
4 8 6|5 1 7|. . 3
2 9 5|4 3 8|6 7 1
3 1 7|9 6 2|4 5 8
-----+-----+-----
7 5 3|2 4 1|. . 6
8 2 .|. . 6|. 1 .
1 6 .|. . 3|. . .


I removed both conflicting 5's in R2C5 and R9C5.
I removed the 1 in R9C9 which conflicted in all 3 units.
I first removed the conflicting 6 in R8C5. Removing the other 6 in column 5 would have been useless. Without the 6, the puzzle has 4 solutions, so it needed another clue. One of the 2 other positions for 6 in box 8 would not cause a unique solution, but R8C6 does.

So here it is. Fixed using logic only. The remainder of this puzzle can be solved with singles.:D

Ruud.
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Postby QBasicMac » Tue Apr 18, 2006 1:39 pm

Ruud wrote:I like to fix broken things.


Nice job!

Mac
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