Consider this example

r3c9-r3c1-r1c2 is an xyz-wing of 9. But, there is no elimination available at the intersection r3c2 or r3c3 since the cells are already occupied by 5 and 2 respectively. However, simple logic tells me that if r3c9=9 then r2c4=9. With this piece of additional information, the intersections of the xyz-wing can now be extended to cover cells r2c1, r2c2 and r2c3 also. This allows a 9 to be eliminated from r2c1 and r2c3; and the puzzle can be easily solved from here.
With simple xyz-wing:
When r3c9=9 => r3c2,3 not=9.
When r3c9=7 => r3c1 & r1c2=89 => r3c2,3 not=9.
With this extended xyz-wing (xyz-chain):
When r3c9=9 => r2c4=9 => r2c1,2,3 not=9.
When r3c9=7 => r3c1 & r1c2=89 => r2c1,2,3 not=9.