Pat actually gave you the hardest step (*) of this puzzle, but it's not all you have left. I would recommend taking the easier pickings first and save the hidden triple/naked quad last, after which it's singles to the end. Of course you can use it earlier if you happen to spot it, but it's not the natural progression to look for those when you still have pointing pairs and naked triples around (*). In this case taking it early may actually make things a bit harder as it reveals an unhelpful extra naked triple.
(*) Added: this ordering only applies if pencil marks are being used -- otherwise hidden triples are easier than naked triples.
So, you're currently here:
- Code: Select all
.--------------------.------------------.--------------------.
| 4 23578-6 356 | 9 3678 1 | 258 56 568 |
| 389 2389-6 136 | 2348 368 5 | 28 7 14689 |
| 5789 25789-6 156 | 248 678 468 | 3 14569 145689 |
:--------------------+------------------+--------------------:
| 135 *35(6) 8 | 13 9 36 | 4 2 7 |
|%(13) *4(6)-3 2 | 48-13 68-3 7 | 9 %(135) %(135) |
| 139 349 7 | 5 2 34 | 6 8 13 |
:--------------------+------------------+--------------------:
| 6 78 35 | 78 4 9 | 1 35 2 |
| 3578 3578 4 | 6 1 2 | 578 359 3589 |
| 2 1 9 | 378 5 38 | 78 46 468 |
'--------------------'------------------'--------------------'
There's an unexecuted pointing pair (6)r56c2 (*), as well as a naked triple (135)r5c189 (%). I've shown their eliminations. The naked triple is important, because it gives you lots of further eliminations and placements:
-> Hidden single (1)r4c4
-> Pointing pair (3)b5/c6 -> -3 r9c6
-> Naked singles (8)r9c6, (7)r7c4, (3)r9c4, (2)r7c2, (7)r9c7
[Added: As eleven points out below, the eliminations of the naked triple (135) can also be seen through its coupled hidden triple (468), which is easier to spot if pencil marks aren't being used.]
After that you're here, and now is the time to look for more difficult patterns like the hidden triple/naked quad:
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.-------------------.---------------.------------------------.
| 4 237-5 3-56 | 9 378-6 1 |*2(5)8 *(56) *(56)8 |
| 389 239 136 | 248 368 5 |*28 7 149-68 |
| 5789 2579 156 | 248 678 46 | 3 149-56 149-568 |
:-------------------+---------------+------------------------:
| 35 356 8 | 1 9 36 | 4 2 7 |
| 13 46 2 | 48 68 7 | 9 135 135 |
| 139 349 7 | 5 2 34 | 6 8 13 |
:-------------------+---------------+------------------------:
| 6 8 35 | 7 4 9 | 1 35 2 |
| 357 357 4 | 6 1 2 | 58 359 3589 |
| 2 1 9 | 3 5 8 | 7 46 46 |
'-------------------'---------------'------------------------'
Look at box 3. There are 7 empty cells and thus 7 digits missing. Luckily, they happen to form two subsets 4+3: a naked quad (2568) and a hidden triple (149), which means we can eliminate the extra candidates from the hidden set. Pat implicated only the hidden triple, but since you're solving with candidates, it's probably easier to see the naked quad (but it depends on your solving style). Without candidates the hidden triple would definitely be the easier, because you can see that the givens (149) in both row 1 and column 7 leave only three places for those digits in box 3.
Either way you get the same eliminations in the box, but with the hidden triple approach you then have to perform two pointing pair/triple operations with the now locked (5) and (6) in r1c789. Using the naked quad would actually give you both the box and the row eliminations in a single move (but that's a bit advanced way of seeing it). After that it's singles to the end.
If you learn to spot the last move yourself, you can congratulate yourself. It's pretty much the third hardest basic move there is. The only things harder would be a naked quad/hidden quad pairing and the very rare naked quin/hidden quad pairing. Even though they're counted as basic moves, I'd say they're often harder to spot than some "advanced" moves (especially Unique Rectangles and X-Wings which are almost trivial compared to these).