The New Sudoku Players' Forum

[200e200w]

Code: Select all

. . .|. . 9|. 3 .
. . 4|3 . .|. 2 .
. 3 .|. . 1|4 . 7
-----+-----+-----
. . .|. . 6|9 . .
8 . .|4 . 5|. . 2
. . 1|2 . .|. . .
-----+-----+-----
3 . 8|9 . .|. 7 .
. 9 .|. . 3|1 . .
. 6 .|5 . .|. . .


Enjoy solving!

200e200w

[Cenoman]

Code: Select all

 +---------------------+-----------------+----------------------+
 |  7     1258   256   |  68   4    9    | B568   3      1568   |
 | f169  e18     4     |  3    5    7    | d68    2      1689   |
 | f569   3     a569   |  68   2    1    |  4    A5689   7      |
 +---------------------+-----------------+----------------------+
 | G24-5  245    3     |  1    7    6    |  9     458    458    |
 |  8     7     b69    |  4    39   5    | c36    1      2      |
 | f69    45     1     |  2    39   8    |  7     456    3456   |
 +---------------------+-----------------+----------------------+
 |  3     145    8     |  9    16  D24   | C256   7      456    |
 | G24-5  9      25    |  7    68   3    |  1     4568   4568   |
 | F14    6      7     |  5    18  E24   |  238   489    3489   |
 +---------------------+-----------------+----------------------+

Kraken row (5)r3c138
(5)r3c1
(5-9)r3c3 = (9-6)r5c3 = r5c7 - (6=8)r2c7 - (8=1)r2c2 - (169=5)r236c1
(5)r3c8 - r1c7 = (5-2)r7c7 = r7c6 - (2=4)r9c6 - r9c1 = (24)r48c1
=> -5 r48c1; stte

[pjb]

Code: Select all

 7      l1258   k256    | 68     4      9      |j56-8   3      156-8   
f169     1-8     4      | 3      5      7      |a68     2      1689   
 569     3       569    | 68     2      1      | 4      5689   7     
------------------------+----------------------+---------------------
 245     245     3      | 1      7      6      | 9      458    458   
 8       7      d69     | 4     c39     5      |b36     1      2     
e69      45      1      | 2      39     8      | 7      456    3456   
------------------------+----------------------+---------------------
 3       145     8      | 9      16     24     | 256    7      456   
 245     9       25     | 7      68     3      | 1      4568   4568   
g14      6       7      | 5      18    h24     |i238    489    3489   


Digging deep for a one-liner:
(8=6)r2c7* - (6=3)r5c7^ - (3=9)r5c5 - (9=6)r5c3~ - (6=9)r6c1 - (69=1)r2c1*# - (1=4)r9c1 - (4=2)r9c6 - (23=8)r9c7^ - (68=5)r1c7*% - (56=2)r1c3~ - (125=8)r1c2#% => -8 r1c79, r2c2; stte

Phil

[SpAce]

Digging deep for a one-liner:
(8=6)r2c7* - (6=3)r5c7^ - (3=9)r5c5 - (9=6)r5c3~ - (6=9)r6c1 - (69=1)r2c1*# - (1=4)r9c1 - (4=2)r9c6 - (23=8)r9c7^ - (68=5)r1c7*% - (56=2)r1c3~ - (125=8)r1c2#% => -8 r1c79, r2c2; stte

Hi Phil! That's a cool solution and, as far as I'm concerned, pretty easily understood from your notation. For some reason I really like nets However, I think memory chains would be a great deal more readable if the markers were located on logical sides of the nodes to indicate which is "sending" a remote signal and which is "receiving" one. In your chain every marker looks like a sending node to my eye. It's especially confusing when one node is in both roles, and we have two of those here. How about this minor change:

(8=6)r2c7* - (6=3)r5c7^ - (3=9)r5c5 - (9=6)r5c3~ - (6=9)r6c1 - *(69=1)r2c1# - (1=4)r9c1 - (4=2)r9c6 - ^(23=8)r9c7 - *(68=5)r1c7% - ~(56=2)r1c3 - #%(125=8)r1c2

My preference would be to also reorder some digits to make it even clearer which ones are affected by which memory:

(8=6)r2c7* - (6=3)r5c7^ - (3=9)r5c5 - (9=6)r5c3~ - (6=9)r6c1 - *(69=1)r2c1# - (1=4)r9c1 - (4=2)r9c6 - ^(32=8)r9c7 - *(68=5)r1c7% - ~(65=2)r1c3 - #%(152=8)r1c2

Or:

(8=6)r2c7* - (6=3)r5c7^ - (3=9)r5c5 - (9=6)r5c3~ - (6=9)r6c1 - *(96=1)r2c1# - (1=4)r9c1 - (4=2)r9c6 - ^(23=8)r9c7 - *(86=5)r1c7% - ~(56=2)r1c3 - #%(215=8)r1c2

I guess the markers could even be embedded with the digits, but it gets kind of ugly:

(8=6*)r2c7 - (6=3^)r5c7 - (3=9)r5c5 - (9=6~)r5c3 - (6=9)r6c1 - (9*6=1#)r2c1 - (1=4)r9c1 - (4=2)r9c6 - (^32=8)r9c7 - (*68=5%)r1c7 - (~65=2)r1c3 - (#1%52=8)r1c2

(8=6*)r2c7 - (6=3^)r5c7 - (3=9)r5c5 - (9=6~)r5c3 - (6=9)r6c1 - (9*6=1#)r2c1 - (1=4)r9c1 - (4=2)r9c6 - (2^3=8)r9c7 - (8*6=5%)r1c7 - (5~6=2)r1c3 - (2#1%5=8)r1c2

What do you think?