a value that is placed collects all the values of its BRT-expansion minus those already placed so a value that has in its BRT-expansion all the other values regardless of its position in the path will collect all the remaining values
it is unlikely that from the 36 values i have i will get a longer expansion path than the one you found because in this selection there are 10 such values so there are 26 values left to organize into expansion steps before ending with any of the 10
what is important in this exercise is to have a good starting selection
here the BRT-expansion of your values:
- Code: Select all
1: ((13 7))
1: ((17 2))
1: ((20 9))
1: ((23 3))
1: ((26 6))
1: ((36 7))
1: ((42 4))
1: ((51 8))
1: ((52 4))
1: ((56 4))
1: ((66 9))
2: ((10 4) (20 9))
2: ((15 9) (20 9))
2: ((24 2) (20 9))
2: ((79 9) (66 9))
2: ((80 4) (56 4))
3: ((4 4) (10 4) (20 9))
3: ((14 8) (13 7) (23 3))
3: ((27 4) (26 6) (23 3))
4: ((1 1) (10 4) (20 9) (2 2))
4: ((2 2) (1 1) (10 4) (20 9))
4: ((48 7) (36 7) (74 7) (56 4))
4: ((74 7) (56 4) (48 7) (36 7))
6: ((41 7) (48 7) (36 7) (74 7) (13 7) (56 4))
9: ((38 1) (1 1) (10 4) (48 7) (74 7) (20 9) (2 2) (56 4) (36 7))